Re: Inverse Interpolation
- To: mathgroup at smc.vnet.net
- Subject: [mg120972] Re: Inverse Interpolation
- From: "Oleksandr Rasputinov" <oleksandr_rasputinov at hmamail.com>
- Date: Fri, 19 Aug 2011 06:35:43 -0400 (EDT)
- Delivered-to: l-mathgroup@mail-archive0.wolfram.com
- References: <j2iens$bkv$1@smc.vnet.net>
On Thu, 18 Aug 2011 08:24:44 +0100, WetBlanket <wyvern864 at gmail.com> wrote: > Previously, the following code could be used to use the Plot functions > algorithm to select point at which to evaluate a function to assist in > obtaining a good numerical interpolation. In Version 8 this code does > not seem to work ( at least for me). Can someone assist me by showing > how this task is best accomplished in Version 8. I use the Cos > function in this example for simplicity. Clearly, numerical > interpolation is not needed to obtain an inverse for the Cos. > > list={}; > F = Cos[x]; > > Plot[ ( ss=F; AppendTo[list, {ss,x}]; ss), {x,-1,1}, PlotPoints- >> 1000, > PlotRange->All, AxesLabel->{"x","F"}] > > Thanks for the help. > list = {}; F = Cos[x]; Plot[ F, {x, -1, 1}, PlotPoints -> 1000, PlotRange -> All, AxesLabel -> {"x", "F"}, EvaluationMonitor :> AppendTo[list, {F, x}] ]