       Re: Plot Manipulate Table

• To: mathgroup at smc.vnet.net
• Subject: [mg121122] Re: Plot Manipulate Table
• From: Peter Pein <petsie at dordos.net>
• Date: Mon, 29 Aug 2011 07:43:50 -0400 (EDT)
• Delivered-to: l-mathgroup@mail-archive0.wolfram.com
• References: <j3fgc2\$fbm\$1@smc.vnet.net>

```Am 29.08.2011 09:50, schrieb . .:
> Hi all,
>
> I want to plot
>
> ConditionalExpression[(
>  a^y \[Lambda] (a + \[Lambda])^(-1 - y) Gamma[1 + y])/y!,
>  Re[a + \[Lambda]] > 0 && Re[y] > -1]
>
> y is the variable. The value of may be 0.1 and the value of [\Lambda]
> can be 1. It would be nice if "a" can be manipulable.
>
> I have seen this post,
>
> http://forums.wolfram.com/student-support/topics/26441
>
> but can not port the idea to my case. I have tried,
>
> Manipulate[
>  ListLinePlot[
>   Table[(a^y \[Lambda] (a + \[Lambda])^(-1 - y) Gamma[1 + y])/
>    y!, {y, 0, 10, 1}], PlotRange -> {0, 1}, DataRange -> {0, 5},
>   PlotMarkers -> Automatic], {a, 0.01, 1, 0.01}]
>
> but obviously
>

Hi,

if you did not assign a value to lambda, the plot command does not know
what to do with the symbilc values.

Try

Manipulate[
With[{\[Lambda]=1},
...
]]

or add a slider for lambda too:

Manipulate[
ListLinePlot[
(* Gamma[1+ y] and y! cancel of course *)
Table[a^y*\[Lambda]*(a + \[Lambda])^(-1 - y), {y, 0, 10}],
PlotRange -> {0, 1}, DataRange -> {0, 5},
PlotMarkers -> Automatic
], {a, 0.01, 1, 0.01}, {{\[Lambda], 1}, 0, 2, 0.05}
]

hth,
Peter

```

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