Re: Evaluation of limit
- To: mathgroup at smc.vnet.net
- Subject: [mg115738] Re: Evaluation of limit
- From: Bill Rowe <readnews at sbcglobal.net>
- Date: Wed, 19 Jan 2011 05:29:53 -0500 (EST)
On 1/18/11 at 5:52 AM, jogc at mecheng.iisc.ernet.in (Dr. C. S. Jog) wrote: >If I give the command >In[1]:= Limit[Cosh[x]+Sinh[x]^2*Log[Tanh[x/2]],x->Infinity] >I get >x 2 >Out[1]= Limit[Cosh[x] + Log[Tanh[-]] Sinh[x] , x -> Infinity] >2 >instead of zero. This result can be verified numerically (of course, >by using higher precision than the default). I get In[1]:= Limit[Cosh[x] + Sinh[x]^2*Log[Tanh[x/2]], x -> Infinity] Out[1]= 0 In[2]:= $Version Out[2]= 8.0 for Mac OS X x86 (64-bit) (November 6, 2010) What version of Mathematica are you using?