Re: Evaluation of limit
- To: mathgroup at smc.vnet.net
- Subject: [mg115746] Re: Evaluation of limit
- From: Bob Hanlon <hanlonr at cox.net>
- Date: Wed, 19 Jan 2011 05:31:28 -0500 (EST)
$Version
"8.0 for Mac OS X x86 (64-bit) (November 6, 2010)"
Limit[Cosh[x] + Sinh[x]^2*Log[Tanh[x/2]],
x -> Infinity]
0
Bob Hanlon
---- "Dr. C. S. Jog" <jogc at mecheng.iisc.ernet.in> wrote:
=============
If I give the command
In[1]:= Limit[Cosh[x]+Sinh[x]^2*Log[Tanh[x/2]],x->Infinity]
I get
x 2
Out[1]= Limit[Cosh[x] + Log[Tanh[-]] Sinh[x] , x -> Infinity]
2
instead of zero. This result can be verified numerically (of course, by
using higher precision than the default).
Regards
C. S. Jog