Re: Simplifying Bessel Functions
- To: mathgroup at smc.vnet.net
- Subject: [mg121421] Re: Simplifying Bessel Functions
- From: Bob Hanlon <hanlonr at cox.net>
- Date: Wed, 14 Sep 2011 05:16:17 -0400 (EDT)
- Delivered-to: l-mathgroup@mail-archive0.wolfram.com
- Reply-to: hanlonr at cox.net
a = BesselJ[1, BesselJZero[0, 1]]/BesselJ[2, BesselJZero[0, 1]];
b = BesselJZero[0, 1]/2;
{a - b, 1/a - 1/b} // FullSimplify
{0, 0}
sub = {a -> b, 1/a -> 1/b};
1/(2 rho) (6 - (3 BesselJ[2, BesselJZero[0, 1]] BesselJZero[0, 1])/
BesselJ[1, BesselJZero[0, 1]] + BesselJZero[0, 1]^2) /. sub
BesselJZero[0, 1]^2/(2 rho)
Bob Hanlon
---- Sam Takoy <sam.takoy at yahoo.com> wrote:
=============
Hi,
As a follow up, when I try
1/(2 rho) (6 - (3 BesselJ[2, BesselJZero[0, 1]] BesselJZero[0, 1])/
BesselJ[1, BesselJZero[0, 1]] +
BesselJZero[0, 1]^2) // FullSimplify
I don't get
1/2 BesselJZero[0, 1]
which is what it is!
Thanks again,
Sam