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Re: Inverse of function

  • To: mathgroup at
  • Subject: [mg121420] Re: Inverse of function
  • From: "Oleksandr Rasputinov" <oleksandr_rasputinov at>
  • Date: Wed, 14 Sep 2011 05:16:07 -0400 (EDT)
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  • References: <j4neqn$54e$>

On Tue, 13 Sep 2011 12:29:27 +0100, Berthold Hamburger  
<b-hamburger at> wrote:

> Hi,
> I stumbled over a small riddle using mathematica 8. Asking for the
> inverse of the function f(x)= x^2, I receive the solution: f^(-1)(x)
> = =C2=B1sqrt(x)
> Why is that so? I had rather expected an error message.
> Regards

Perhaps this is a result of the particular way in which you asked, or some  
assumptions inadvertently applied? In a new session, InverseFunction  
behaves as expected:

In[1] := InverseFunction[#^2 &]

During evaluation of In[1] := InverseFunction::ifun: Inverse functions are  
being used. Values may be lost for multivalued inverses.

Out[1] = -Sqrt[#1] &

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