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Re: Inverse of function

  • To: mathgroup at
  • Subject: [mg121469] Re: Inverse of function
  • From: Berthold Hamburger <b-hamburger at>
  • Date: Fri, 16 Sep 2011 05:48:09 -0400 (EDT)
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  • References: <j4neqn$54e$> <j4prkq$fn5$>

On Wed, 14 Sep 2011 09:20:26 +0000 (UTC), Simon 
<simonjtyler at> wrote:
> Exactly what code did you use to get the inverse function?

Hi Simon,

I used the free form input in that form: "inverse function of 
f(x)=x^2", so I essentially used Wolfram alpha

My point or rather my question was however, why Mathematica returns a 
solution where there should be none, as to my understanding f(x)=x^2 
cannot be inverted. But then my understanding is quite limited, so 
please bear with me if this is just a lapse of knowledge on my part 


Berthold Hamburger - Cellist/Spain | | 
Sent from my Android Galaxy tab with Kaiten Mail.

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