Re: Group and Replace itens sequence in a list
- To: mathgroup at smc.vnet.net
- Subject: [mg127818] Re: Group and Replace itens sequence in a list
- From: Ulrich Arndt <ulrich.arndt at data2knowledge.de>
- Date: Thu, 23 Aug 2012 20:52:55 -0400 (EDT)
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This one requires no X ls = ReplaceRepeated[l, {x___, a, b, a, y___} -> {{x}, {y}}] Extract[ls, Position[ls, {a___?AtomQ}]] Ulrich Am 23.08.2012 um 08:52 schrieb Murta: > Hi All > > I have a simple problem that is: > > l={1,2,3,a,b,a,4,5,6,a,b,c,7,8,9,a,b,a,10,11,12} > > I want to replace all a,b,a sequence by X to get: > > l={1,2,3,X,4,5,6,a,b,7,8,9,X,10,11,12} > > Then I want to group it by X intervals as > l={{1,2,3},{4,5,6,a,b,7,8,9},{10,11,12}} > > If I don't need to put the intermediate X, even better! > I think the with pattern, RaplaceAll and DeleteCases I can do It. Some clue? > Tks > Murta > > >
- References:
- Group and Replace itens sequence in a list
- From: Murta <rodrigomurtax@gmail.com>
- Group and Replace itens sequence in a list