Re: New to Mathematica
- To: mathgroup at smc.vnet.net
- Subject: [mg126392] Re: New to Mathematica
- From: "J.Jack.J." <jack.j.jepper at googlemail.com>
- Date: Sun, 6 May 2012 20:29:16 -0400 (EDT)
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On May 6, 8:25 am, David Bailey <d... at removedbailey.co.uk> wrote: > On 05/05/2012 09:16, J.Jack.J. wrote: > > > > > > > > > > > On May 3, 9:40 am, "J.Jack.J."<jack.j.jep... at googlemail.com> wrote: > >> Hi, > > >> I have just downloaded my free trial version of Mathematica. > >> I only need it for one thing (as yet, anyway), and I wonder whethe= r > >> someone can help me in step-by-step fashion to get what I want. I need > >> the solution to the following (I might make amendments to the values): > > >> "For any integer k, let r(k) be x such that > > >> (x/ln(x))*(1 + 1/ln(x)) = 108.2 + k) > > >> product (k = 0 to 3000) (1-1/r(k))" > > >> With many thanks in advance. > > > Can nobody help me with this? Just for a Newbie? > > As most will realise, the first lines define my function and the > > product (k = 0 to 3000) (1-1/r(k)) > > is my desired calculation. I need to know what inputs to use. > > > With thanks in advance. > > If you press F1, you will enter the help system. Once there, you could > try looking up log and product. The examples will give you the basics of > Mathematica syntax, and you can cut and paste them into your notebook, > and alter them as desired. > > David Baileyhttp://www.dbaileyconsultancy.co.uk Have tried and failed, tried and failed, with this method! Can somebody give me the requisite inputs? Note that I need to add the condition that x be the highest integer for which <definition of r(k)>. With thanks.