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Re: Formula Stirlinga

  • To: mathgroup at smc.vnet.net
  • Subject: [mg130699] Re: Formula Stirlinga
  • From: DC <b.gatessucks at gmail.com>
  • Date: Fri, 3 May 2013 03:52:49 -0400 (EDT)
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  • References: <klsg67$t99$1@smc.vnet.net>

It looks better if you take the logs :

n = 1000;
N[Log[Factorial[n]] - (1/2 Log[2 Pi n] + n Log[n] - n)]




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