Re: Plotting Data By State

• To: mathgroup at smc.vnet.net
• Subject: [mg132676] Re: Plotting Data By State
• From: Joe Gwinn <joegwinn at comcast.net>
• Date: Sat, 3 May 2014 03:40:55 -0400 (EDT)
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• References: <ljvdb7\$ba0\$1@smc.vnet.net>

```In article <ljvdb7\$ba0\$1 at smc.vnet.net>, Alexandra Lipson
<lipson.alexandra at gmail.com> wrote:

> Hello All,
>
> I am trying to plot manipulated crime data from 1973 on a United States map
> to show the comparisons of the number of arrests of certain crimes to the
> number of actual crimes committed in a specific year. I want to show
> whether there are more arrests than crimes or more crimes than arrests in
> each state.
>
> I am new to Mathematica and would love some help. Here is what I have so
> far...(data manipulation still in progress):
>
> data = Import["/Users/allielipson/Desktop/USArrests.csv"];
> alPop = 4000000;
> akPop = 300000;
[snip]
>
> crimeData =
>  Import["http://hci.stanford.edu/jheer/workshop/data/crime/CrimeStatebyState.csv";]
[snip]
>

The general pattern is as follows:

ListPlot[ Transpose[{listA, listB}] ]

The lists must have the same length, or Transpose will bark at you.

ListPlot[ Transpose[{listA, listB}], Joined->True] will draw lines
between the points.

ListPlot[ {Transpose[{listA, listB}], Transpose[{listC, listD}]} ] will
co-plot the two curves.

And so on.

One can also do the Transposes in advance:

listAB = Transpose[{listA, listB}];

listCD = Transpose[{listC, listD}];

The trailing semicolons prevent the whole matrix from being printed out
at length.

ListPlot[{listAB, listCD}, Joined->True]

Joe Gwinn

```

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