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Count[{Unevaluated[a]},Unevaluated[a]]


 Hi cummunity,

 the above gives - a little bit surprisingly for me - 0.
 With a third argument: Count[{Unevaluated[a]},Unevaluated[a],{-1}]
 the result is 1 (as expected). Using On[] one sees that 
 Count "evaluates" its arguments. Literal instead of Unevaluated gives
 a similar result.
 Why does Count do this?

 Thanks for an answer,

 Michael Trott

 trott at physik.tu-ilmenau.de







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