|
[Date Index]
[Thread Index]
[Author Index]
Count[{Unevaluated[a]},Unevaluated[a]]
- To: mathgroup at yoda.physics.unc.edu
- Subject: Count[{Unevaluated[a]},Unevaluated[a]]
- From: Michael.Trott at physik.tu-ilmenau.de
- Date: Mon, 23 Nov 1992 19:10:50 +0000
Hi cummunity,
the above gives - a little bit surprisingly for me - 0.
With a third argument: Count[{Unevaluated[a]},Unevaluated[a],{-1}]
the result is 1 (as expected). Using On[] one sees that
Count "evaluates" its arguments. Literal instead of Unevaluated gives
a similar result.
Why does Count do this?
Thanks for an answer,
Michael Trott
trott at physik.tu-ilmenau.de
Prev by Date:
nonlinear two point boundary problems
Next by Date:
Bug report / Re: Mathematica/MS Word/Postscript problem
Previous by thread:
Materials for Multivariable Calculus
Next by thread:
Bug report / Re: Mathematica/MS Word/Postscript problem
|