Re: HypergeometricPFQ
- To: mathgroup at yoda.physics.unc.edu
- Subject: Re: HypergeometricPFQ
- From: victor
- Date: Thu, 19 Nov 92 12:00:36 CST
This is a solution of your problem:
Unprotect[ HypergeometricPFQ]
HypergeometricPFQ[{a_, b_}, {c_}, arg_ ] :=
Hypergeometric2F1[ a, b, c, arg] /;
(And @@ (NumberQ /@ {a,b,c,arg})) && Accuracy[{a,b,c,arg}] < Infinity
Protect[ HypergeometricPFQ]
Begin forwarded message:
Date: Wed, 18 Nov 92 14:56:12 CST
From: lsf at holmes.astro.nwu.edu (Sam Finn)
To: mathgroup at yoda.physics.unc.edu
Subject: HypergeometricPFQ
Re: HypergeometricPFQ
Mathematica 2.1 on a SPARC2
The evaluation rules for HypergeometricPFQ are messed up:
In[1]:= Integrate[1/(x^(7/3)(x^2+1.44^2)),{x,1,Infinity}]
5 8
Out[1]= 0.3 HypergeometricPFQ[{1, -}, {-}, -2.0736]
3 3
In[2]:= N[%]
Out[2]= 0.3 HypergeometricPFQ[{1.,1.66667}, {2.66667}, -2.0736]
Now, I contacted support at wri.com with this bug, and after a week of
waiting for a reply I phoned. I was told that they don't know why this
is happening, but that it is fixed in 2.2. No, 2.2 is not available: it
is Wolfram internal. The only workaround is to hand substitute into
Hypergeometric2F1. When asked if a bug fix would be available for 2.1,
I was told that it is fixed in 2.2.
Since Wolfram won't help (except when it comes to spending my money), I
thought maybe someone in the mathgroup has been through this and
tracked down the problem (probably in HypergeometricPFQ.m). Regardless,
I thought you might be interested in hearing a testimonial to the
quality technical support that is yours when you become a Mathematica
Plus subscriber.
Thanks for any help you can offer,
L. S. Finn
Physics and Astronomy
Northwestern University
P.S. And also, will somebody please remind me why I even bother trying
to make productive use of Mathematica?