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MathGroup Archive 1993

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Re: Differrence between version 2.03 and 2.1?

  • To: mathgroup at yoda.physics.unc.edu
  • Subject: Re: Differrence between version 2.03 and 2.1?
  • From: Garth Payne <pan at math.psu.edu>
  • Date: Thu, 25 Feb 93 10:24:48 -0500

> 	While I have your attention, I wonder if you know an
> easy way to turn the solutions of a Solve from a list of 
> replacement rules to simply elements of a list. Suppose
> Solve[x==f[x],{x}]={{x->a},{x->b},{x->c}}, I want the list
> {a,b,c} instead. I have come up with a cumbersome way of
> doing this which is
> solns=Table[x/.Flatten[solnlist=Solve[x==f[x],{x}]][[i]],
> 	{i,Length[solnlist]}]
> but I know there must be a better way.
> 
> 	
> Thanks
> Leon
> 
> 

The command

     x /. Solve[x==f[x],{x}] 

is what you want.

Garth Payne







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