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Re: Arbitrary Precision Calculation Of Pi


	> A colleague of mine asked me how Mathematica calculates Pi
	> to an arbitrary precision.  I haven't a clue.  Do any
	> of you know?!


It is based on the Chudnovsky formula:

   640320^(3/2)/(6541681608 Pi) ==
    Sum[(n + 13591409/545140134) (6n)! (-1)^n/
          ((3n)! (n!)^3 640320^(3n)), {n, 0, Infinity}]

The sum converges like a geometric series with ratio nearly 10^-14.

Jerry B. Keiper
keiper at wri.com
Wolfram Research, Inc.





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