Defining your own Derivative
- To: mathgroup at christensen.cybernetics.net
- Subject: [mg810] Defining your own Derivative
- From: P.Jemmer at sussex.ac.uk (Patrick Jemmer)
- Date: Fri, 21 Apr 1995 01:49:36 -0400
- Organization: University of Sussex
I have a problem where I need to do something like the following, and
define a slightly new "derivative" operator:
(* define variables *)
(* define derivatives of derivatives *)
(* this bit works ok *)
(* define derivatives of variables *)
(* However there are problems _here_ *)
For example if I try to look at D[x,ri] I get the answer 0, rather
than the answer D[mRi/R^(4/3),ri].
How do I make MMA apply the cahin rule (or whatever) to these new
definitions of "D". Do I explicitly have to redefine, for example:
The problem is that I initially defined a whole new function "df"
and wrote out all these properties so that it worked, and I was
looking for something a little more elegant.
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