Re: REQ: (a+b)n
- To: mathgroup at smc.vnet.net
- Subject: [mg6372] [mg6372] Re: [mg6358] REQ: (a+b)n
- From: Robert Pratt <rpratt at math.unc.edu>
- Date: Fri, 14 Mar 1997 14:54:08 -0500 (EST)
- Sender: owner-wri-mathgroup at wolfram.com
The formula for the nth power of the binomial a+b is
(a+b)^n = Sum[Binomial[n,k] a^k b^(n-k), {k,0,n}]
where Binomial[n,k] (built-in Mma function) is the binomial coefficient
n!/(k!(n-k)!).
Rob Pratt
Department of Mathematics
The University of North Carolina at Chapel Hill
CB# 3250, 331 Phillips Hall
Chapel Hill, NC 27599-3250
rpratt at math.unc.edu
http://www.math.unc.edu/Grads/rpratt/
On Thu, 13 Mar 1997, Gerard Wisse wrote:
> Hi All,
>
> Who could help me and give the formule of the following:
>
> (a+b)2 = 1a2 + 2ab + 1b2
>
> What is the formule of (a+b)n ???
> n is a variable number.
>
> Thanx!!!
>
> Yiorgos Wisse
> Gerard.Wisse at nlehvfm1.origin.nl
>
>