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MathGroup Archive 1997

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Re: REQ: (a+b)n

  • To: mathgroup at smc.vnet.net
  • Subject: [mg6376] [mg6376] Re: [mg6358] REQ: (a+b)n
  • From: seanross at worldnet.att.net
  • Date: Fri, 14 Mar 1997 14:54:26 -0500 (EST)
  • Sender: owner-wri-mathgroup at wolfram.com

Gerard Wisse wrote:
> 
> Hi All,
> 
> Who could help me and give the formule of the following:
> 
> (a+b)2 = 1a2 + 2ab + 1b2
> 
> What is the formule of (a+b)n ???
> n is a variable number.
> 
> Thanx!!!
> 
> Yiorgos Wisse
> Gerard.Wisse at nlehvfm1.origin.nl


Your e-mail got a little garbled.  I am assuming you want the equation 
for (a+b)^n.  There is no general formula for arbitrary n, but for 
n=integer, this is called the binomial expansion.  You can find the 
formula in any standard mathematical handbook like the CRC mathematical 
tables.  I believe the formula is 

(a+b)^n=Sum[(n-i)!/n! a^i b^(n-i),{i,0,n}]

But you'd better check me on that since I don't have my copy of CRC in 
front of me right now.


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