[Date Index]
[Thread Index]
[Author Index]
Re: [Q] Why Integrate[1/x,x] <> Log[Abs[x]] with Mma 2.2 ?
*To*: mathgroup at smc.vnet.net
*Subject*: [mg8788] Re: [Q] Why Integrate[1/x,x] <> Log[Abs[x]] with Mma 2.2 ?
*From*: "Stephen P Luttrell" <luttrell at signal.dra.hmg.gb>
*Date*: Thu, 25 Sep 1997 12:26:22 -0400
*Organization*: Defence Evaluation and Research Agency
*Sender*: owner-wri-mathgroup at wolfram.com
Denis Barbier <barbier at cmapx.polytechnique.fr> wrote in article
<5vt7q9$ghc at smc.vnet.net>...
> it is well known that Integrate[1/x,x] = Log[Abs[x]], but Mma 2.2 returns
> Log[x].
>
> How can i correct this ?
I have checked that the following works correctly in Mathematica 3.0. I
don't know whether version 2.2 will behave in the same way.
Log[x] is the correct result, where x is a complex number.
If you want to evaluate the definite integral between two points on the
positive real line (which is what I suspect you want to do - correct me if
I'm wrong), then Log[x2]-Log[x1] will give the same result as
Log[Abs[x2]]-Log[Abs[x1]].
If you want to evaluate the integral along a piecewise linear contour whose
corners are specified by the list {x1,x2,...,xn}, where the xi are complex
numbers, then evaluate Integrate[1/x,{x,x1,x2,...,xn}]. For instance,
Integrate[1/x,{x,1,I,-1,-I,1}] will yield the result 2 I \[Pi], as
expected.
--
Stephen P Luttrell
luttrell at signal.dra.hmg.gb
Adaptive Systems Theory 01684-894046 (phone)
Room EX21, DERA 01684-894384 (fax)
Malvern, Worcs, WR14 3PS, U.K.
http://www.dra.hmg.gb/cis5pip/Welcome.html
Prev by Date:
**Re: FindMinimum on a potentially Complex-valued function**
Next by Date:
**need help**
Previous by thread:
**Re: [Q] Why Integrate[1/x,x] <> Log[Abs[x]] with Mma 2.2 ?**
Next by thread:
**remote kernel**
| |