Re: Disappearing variables

*To*: mathgroup at smc.vnet.net*Subject*: [mg13794] Re: Disappearing variables*From*: Tobias Oed <tobias at physics.odu.edu>*Date*: Fri, 28 Aug 1998 04:18:19 -0400*Organization*: Old Dominion University*References*: <6rr9u0$15b@smc.vnet.net>*Sender*: owner-wri-mathgroup at wolfram.com

nobody at News.Dal.Ca wrote: > > I want to to define a variable inside a function, as follows: f:=x=123; > Whenever I run f, x should be given the value of 123, and if x doesn't > exist, it should be created. However: > > In[1]:= f:=x=123; > In[2]:=f > Out[2]:=123 > In[3]:=x > Out[3]:=123 ** x exists > In[4]:=Remove[x]; > In[5]:=f > Out[5]:=123 ** f seems to work > In[6]:=x > Out[6]:=x ** x doesn't exist anymore, even though f worked > > It seems like x is created when I initially define f, whereas since f is > SetDelayed, x should be created when I run f. > Does anyone know why x is not created when I run f? > > Vilis Nams You need to look at what Remove x is doing: In[1]:= f:=x=123 In[2]:= ??f Global`f f := x = 123 In[3]:= Remove[x] In[4]:= ??f Global`f f := Removed["x"] = 123 That's where your problem comes from. A way arround this is In[1]:= f:=Evaluate[Symbol["x"]]=123 In[2]:= f Out[2]= 123 In[3]:= x Out[3]= 123 In[4]:= Remove[x] In[5]:= f Out[5]= 123 In[6]:= x Out[6]= 123 In[7]:= ??f Global`f f := Evaluate[Symbol["x"]] = 123 That's the rule mathematica remembers and is not affected by Remove[x] because it does not depend on x. The information you can get using ?? is really practical because it tells you the rules which are associated with symbols without evaluating them, allowing you to see what is really going on. By the way it's pretty instructive to inspecct your symbols and Blank this way when using Verbatim definitions. Enjoy, Tobias