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Eddy Wibowo wrote: > > Hi all netters, > > Suppose that I have an equation of: > Sqrt[x+y]+ 2x + 3y == 0 > > Now, what is the Mathematica-way to find: > Sqrt[x+y] = ??? > y = ??? > > Thanks very much beforehand... > > -Edwin To solve for a symbol in the equation, such as y, use Solve: Solve[Sqrt[x+y]+2 x +3 y==0,y] Solving for a function or something more complicated requires the use of a transormation afterwards Solve[aa+2 x +3 y==0,aa]/.aa->Sqrt[x+y] -- Remove the _nospam_ in the return address to respond.