*To*: mathgroup@smc.vnet.net*Subject*: [mg10318] Re: [mg10298] Simple algebra problem*From*: seanross@worldnet.att.net*Date*: Mon, 5 Jan 1998 22:24:33 -0500*References*: <199801050847.DAA01961@smc.vnet.net.>

Eddy Wibowo wrote: > > Hi all netters, > > Suppose that I have an equation of: > Sqrt[x+y]+ 2x + 3y == 0 > > Now, what is the Mathematica-way to find: > Sqrt[x+y] = ??? > y = ??? > > Thanks very much beforehand... > > -Edwin To solve for a symbol in the equation, such as y, use Solve: Solve[Sqrt[x+y]+2 x +3 y==0,y] Solving for a function or something more complicated requires the use of a transormation afterwards Solve[aa+2 x +3 y==0,aa]/.aa->Sqrt[x+y] -- Remove the _nospam_ in the return address to respond.

**References**:**Simple algebra problem***From:*Eddy Wibowo <ew4516@bristol.ac.uk>