Services & Resources / Wolfram Forums
-----
 /
MathGroup Archive
1998
*January
*February
*March
*April
*May
*June
*July
*August
*September
*October
*November
*December
*Archive Index
*Ask about this page
*Print this page
*Give us feedback
*Sign up for the Wolfram Insider

MathGroup Archive 1998

[Date Index] [Thread Index] [Author Index]

Search the Archive

Re: Simple algebra problem




Eddy Wibowo wrote:

> Suppose that I have an equation of:
>         Sqrt[x+y]+ 2x + 3y == 0
>
> Now, what is the Mathematica-way to find:
>         Sqrt[x+y] = ???
>         y = ???

Eddy:
These are separate rearrangements

In[1]:=
Solve[ (Sqrt[x+y]+ 2x + 3y == 0)/.Sqrt[x+y]->s,s]/.s->Sqrt[x+y]

Out[1]=
{{Sqrt[x + y] -> -2*x - 3*y}}


In[2]:=
Solve[ (Sqrt[x+y]+ 2x + 3y == 0),y]

Out[2]=
{{y -> (1 - 12*x - Sqrt[1 + 12*x])/18},
  {y -> (1 - 12*x + Sqrt[1 + 12*x])/18}} --
Allan Hayes
Training and Consulting
Leicester, UK
hay@haystack.demon.co.uk
http://www.haystack.demon.co.uk
voice: +44 (0)116 271 4198
fax: +44 (0)116 271 8642





  • Prev by Date: Re: Question about FormatType Styles
  • Next by Date: How to learn formatting options
  • Prev by thread: Re: Simple algebra problem
  • Next by thread: Re: Simple algebra problem