Re: Numerical Determinants

*To*: mathgroup at smc.vnet.net*Subject*: [mg13107] Re: Numerical Determinants*From*: hello at there.com (Rod Pinna)*Date*: Tue, 7 Jul 1998 03:44:10 -0400*Organization*: UWA*References*: <6n4o6m$nin@smc.vnet.net> <6n9m67$9hq@smc.vnet.net> <6nnb0k$5em@smc.vnet.net>*Sender*: owner-wri-mathgroup at wolfram.com

In article <6nnb0k$5em at smc.vnet.net>, Paul Abbott <paul at physics.uwa.edu.au> wrote: >Rod Pinna wrote: >Why not? Your problem is clearly a generalized eigenvalue problem. For >non-zero p you can rewrite A.x=p B.x as B.x=(1/p) A.x. For invertible >A you then have Inverse[A].B.x = (1/p) x which is the formula that >you're using. > Which probably indicates that I should have listened better in first year mathematics :) That was the idea I was following, but since it hadn't been mentioned as a method in a couple of the texts I consulted, I thought that there might be something I was missing. Basically, everything talks about inverting the B matrix, but then doesn't mention what to do in B in singular. As the above *seemed* obvious, I thought that there might be a reason it wasn't mentioned. Thanks for the advice. Rod. Rod Pinna (rpinnaX at XcivilX.uwa.edu.au Remove the X for email)