Re: Simple edit ...
- To: mathgroup at smc.vnet.net
- Subject: [mg19333] Re: Simple edit ...
- From: Edward Ouellette <techie at mit.edu>
- Date: Mon, 16 Aug 1999 02:15:00 -0400
- Organization: Massachvsetts Institvte of Technology
- References: <7p5ddb$11r@smc.vnet.net>
- Sender: owner-wri-mathgroup at wolfram.com
Mike, I got it to work by adding another rule: z //. {Sqrt[d+e] ->L, 1 / Sqrt[d+e] -> 1 / L} a + L / a L This may not be the most elegant solution, but it works! cheers, Ed "Michael L. Stokes" wrote: > Consider the following examaple; > > z = (a+Sqrt[d+e])/(a Sqrt[d+e]) > > z //. Sqrt[d+e] ->L > > The replacement function only replaces the instance of Sqrt[d+e] in the > numerator and leaves the instance in the denominator alone. Why does > this not work and what is the work around? > > Regards, > Mike