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MathGroup Archive 1999

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Re: Simple edit ...

  • To: mathgroup at smc.vnet.net
  • Subject: [mg19324] Re: Simple edit ...
  • From: Alan Lewis <alanlewis at home.com>
  • Date: Mon, 16 Aug 1999 02:14:55 -0400
  • Organization: @Home Network
  • References: <7p5ddb$11r@smc.vnet.net>
  • Sender: owner-wri-mathgroup at wolfram.com

FullForm shows why it doesn't work. A work around is

z/.Sqrt[d+e]->L/.(1/Sqrt[d+e])->1/L



"Michael L. Stokes" wrote:
> 
> Consider the following examaple;
> 
> z = (a+Sqrt[d+e])/(a Sqrt[d+e])
> 
> z //. Sqrt[d+e] ->L
> 
> The replacement function only replaces the instance of Sqrt[d+e] in the
> numerator and leaves the instance in the denominator alone.  Why does
> this not work and what is the work around?
> 
> Regards,
> Mike


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