Re: M.U.C.
- To: mathgroup at smc.vnet.net
- Subject: [mg20613] Re: [mg20595] M.U.C.
- From: BobHanlon at aol.com
- Date: Thu, 4 Nov 1999 02:13:29 -0500
- Sender: owner-wri-mathgroup at wolfram.com
eqn = E^(-2 x)(-3 + 10 b - x + 6 a(1 + 5 x)) == 0;
SolveAlways[eqn, x]
{{a -> 1/30, b -> 7/25}}
Bob Hanlon
In a message dated 11/2/1999 6:55:32 AM, roscoe at hazardcounty.org writes:
>How can Mathematica solve the following Linear Operator for a and b?
>(E^(-2 x)((-3) + 10 b - x + 6 a(1 + 5 x)) == 0
>
>By hand it would be :
>(-3+10b+6a)=0
>(-1+30a)=0
>
>a=1/30
>b=whatever
>
>I need mathematica to group the coeeficients of x^0 and x^1, set them equal
>to 0 and solve.
>I am trying to avoid doing the gruoping by hand. Thanks.
>