Re: second y-axis in a graph

*To*: mathgroup at smc.vnet.net*Subject*: [mg20551] Re: [mg20515] second y-axis in a graph*From*: "Wolf, Hartmut" <hwolf at debis.com>*Date*: Sat, 30 Oct 1999 00:14:02 -0400*Organization*: debis Systemhaus*References*: <199910270605.CAA10519@smc.vnet.net.>*Sender*: owner-wri-mathgroup at wolfram.com

Krumm, Anton J schrieb: > > I would like to plot two functions with "DisplayTogether" in > one graphics. However, I would need a second y-axes since > the numbers of the second function are much smaller than > those of the first function. > Is there any way to add a second y-axis and relate a > function to that axis? > A.Krumm Dear Anton, I would be happy to write that function "DisplayTogether" -- you are not alone with your wishes. The basis idea is of course, as you said, to display together two (say arbitrary) graphes. Most needs would comply with demanding for the same range and scale of the x-axes (but having solved the problem for y, that will be a paradigma for x too). However, to me, the scaling that _Mathematica_ applies for plotting graphics is absolutely unpredictable. It not only depends on the plot ranges and the embellishments, but also on the details of the graphs (the functions) and on the setting of arbitrary (and seemingly unrelated) options. Nonetheless I managed to do it with an example, and if you need, you may proceed along these lines to get to where you want, if you're ready to invest a modest amount of trial and error. What did I do? I plotted two (related) functions: p1 = Plot[(Sqrt[2]*x*Sin[2*Pi*x])/E^x, {x, 0, 6}, PlotStyle -> Hue[0.77], Axes -> {None, Automatic}, AxesStyle -> {Hue[0.77]}] p2 = Plot[(x*Cos[2*Pi*x])/E^x, {x, 0, 6}, PlotStyle -> Hue[0.13], AxesOrigin -> {6., 0.}, AxesStyle -> {{GrayLevel[0.]}, {Hue[0.13]}}] Please note, there are different scales (and ranges) for the respective y-axis. p1 has its y-scale to the left, but no x-axes drawn, p2 has an x-axes and its y-scale to the right. We combine these plots attempting to keep their displayed sizes (Show doesn't do, because it combines at the user coordinates): Show[Graphics[{Rectangle[Scaled[{0.05, 0}, {0, 0}], Scaled[{0.95, 1}, {0, 0}], FullGraphics[p1]], Rectangle[Scaled[{0.05, 0}, {0, 0}], Scaled[{0.95, 1}, {0, 0}], FullGraphics[p2]]}]] This graph already comes close to what we want, the scaling is grossly right, you can see the labeled scales to the left and to the right, the colour shows, what belongs to what. The scaled coordinates 0.05 (instead of 0) and 0.95 (instead of 1) made these different y-scales (fully) visible; perhaps sometimes you may have to increase those margins. Yet with this graph the coordinate centers do not match exacly, and the x-scaling is not identical. However you can read off the differences in user coordinates (if you enlarge the graph) with sufficient precision. So after only two trials I arrived at Show[Graphics[{Rectangle[Scaled[{0.05, 0}, {0, 0}], Scaled[{0.95, 1}, {0, 0}], FullGraphics[p1]], Rectangle[Scaled[{0.05, 0}, {-0.01, 0.018}], Scaled[{0.95, 1}, {0.022, 0.018}], FullGraphics[p2]]}]] which seems to be good enough to the naked eye. The advantage of this method is that there is only one singular x-axis. The disadvantage is, that you have to fine tune y-shift and x-shift and x-scaling. If you instead define In[164]:= Plot[(x*Cos[2*Pi*x])/E^x, {x, 0, 6}, PlotStyle -> Hue[0.13], AxesOrigin -> {6., 0.}] In[165]:= Plot[(2*x*Sin[2*Pi*x])/E^x, {x, 0, 6}, PlotStyle -> Hue[0.77]] then the x-axes already scale perfectly right, and you have only to adapt for the y-coordinate of the origin: In[170]:= Show[Graphics[{Rectangle[Scaled[{0.05, 0}, {0, 0}], Scaled[{1, 1}, {0, 0}], FullGraphics[Out[164]]], Rectangle[Scaled[{0.05, 0}, {0, -0.02}], Scaled[{1, 1}, {0, -0.02}], FullGraphics[Out[165]]]}]] If you are at your goal, both printed x-axes match exactly. For many applications, say display systolic and diastolic blood pressure together with the pulse rate (from the same measurement), there exists no common origin for pressure and pulse. To the contrary, you possibly want to shift the curves up or down for clarity, then perhaps the latter method will succeed with just the minimal necessary manual intervention. Perhaps even a better idea would be to go through a siminar procedure with Frames->True. Of course I didn't solve the computational problem; an idea would be: add to the primary graphs some (invisible, hidden or white) objects (with known user coordinates), display the graph to some channel, and from there try to readoff the postscript coordinates of the markers, then calculate the necessary scaling. But perhaps this all is too complicated nonsense, apologizing, Hartmut

**References**:**second y-axis in a graph***From:*"Krumm, Anton J" <AKrumm@splasers.com>

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