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MathGroup Archive 1999

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Re: in center of a triangle

  • To: mathgroup at
  • Subject: [mg19628] Re: in center of a triangle
  • From: phbrf at (Peter Breitfeld)
  • Date: Mon, 6 Sep 1999 04:20:43 -0400
  • Organization: das ist ein breites Feld ...
  • References: <7qqbur$>
  • Sender: owner-wri-mathgroup at

Tom De Vries <tdevries at> schrieb:
> Hello!
> I was wondering if anyone has seen or has written a Mathematica  procedure to
> generate the incenter of a triangle given the vertices of the triangle.  The
> incenter of a triangle is the point at which the angle bisectors meet.  From
> this point you can draw an inscribed circle in the triangle.
> Thanks for any help you could offer on this!!
> Tom De Vries
> Edmonton, Alberta, Canada
Maybe you look for something like this:

        Wc=Flatten[A+(B-A)s/.Solve[C+(u+v)/2 t==A+(B-A)s,{s,t}]];
        Wb=Flatten[A+(C-A)s/.Solve[B+(u+v)/2 t==A+(C-A)s,{s,t}]];
        Wa=Flatten[B+(B-C)s/.Solve[A+(u+v)/2 t==B+(B-C)s,{s,t}]];

This function returns the incenter W of the triangel with vertices A, B
and C and the points Wa, Wb, Wc where the where the bisectors meet the
opposite sides of the triangle, so Wa ist the section point of the
bisector through A with BC.

=--=--=--=--=--=--=--=--=--=--=--=--=  =--=
=--= Peter Breitfeld, Saulgau, Germany        PGP public key: 08548045  =--=--=

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