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MathGroup Archive 1999

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How to find solutions for conditioned equations?

  • To: mathgroup at smc.vnet.net
  • Subject: [mg19861] How to find solutions for conditioned equations?
  • From: d8442803 at student.nsysu.edu.tw (Wen-Feng Hsiao)
  • Date: Sun, 19 Sep 1999 01:20:44 -0400
  • Organization: MIS
  • Sender: owner-wri-mathgroup at wolfram.com

Suppose I have an equation

A(x)= (x+1)/2, for -1<x<=1
    = (3-x)/2, for 1<x<=3
    = 0      , otherwise

Now if I want to find solutions for A(x)==a, how can I otain the 
solutions simultaneously (i.e., represented as (2a-1, 3-2a))? I always 
use the stupid method to solve them separately, but I found it's laborous 
when I have B(x), C(x) needed to be solved together. (I am trying to use 
alpha-cut to proceed the interval operations) Any suggestions?



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