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MathGroup Archive 2000

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[Q] Equation solving?

  • To: mathgroup at smc.vnet.net
  • Subject: [mg23282] [Q] Equation solving?
  • From: research at proton.csl.uiuc.edu (James)
  • Date: Sun, 30 Apr 2000 21:13:34 -0400 (EDT)
  • Organization: University of Illinois at Urbana-Champaign
  • Sender: owner-wri-mathgroup at wolfram.com


Hello!

I'm a newbie to Mathematica
and have a question about what's wrong in the following
expression.
(The parameters are generated by the program, 
 so there're some terms that can be cancelled out.) 

Solve[{ Q1==(2*z+1-1)^2+4*1*1 ,
        k1==(1/Sqrt[Q1])*(v*z-(3/2)*(2*z+1+1-Sqrt[Q1])) ,
        Q2==(2*z+1-1)^2+4*1*1 ,
        k2==(1/Sqrt[Q2])*((6.10-v)* z-(2/2)*(2*z+1+1-Sqrt[Q2])) ,
        (3/2)*(2*z+1+1)+(k1-(3/2))*Sqrt[Q1] ==
              6.10*z-((2/2)*(2*z+1+1)+(k2-(2/2))*Sqrt[Q2])}, {z,v}]

I want to solve the above equations according to 'z',
and I tried several ways in expressing {z,v} or z, {v}, etc
to get an answer(s), but all in vain.

Is there anyone who can tell me how to express the equations?
Sorry about the question, if this is trivial.
Thank you.


James.



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