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Re: question


The equation has a first integral, it is

1/(u'+1)  +  Log[1+u'] + u^2/2= C

were C is the integration constant. So you can
try DSolve as well. Also you can check the NDSolve
solution using this formula.

Alex

"Kevin J. McCann" schrieb:

> The wise words of Abraham Boyarsky on 21 Dec 2000 02:36:29 -0500:
>
> > I believe the following is a Liouville differential equation:
> >
> > u"[x] + u[x](u'[x] +1)^2 = 0
> >
> > on [0,1].
> >
> > How does one solve it?
> >
> >
> This is a nonlinear DE. I would use NDSolve with IC u[0]==1,u'[0]==0 and
> with u[0]==0,u'[0]==1.
>
> Kevin




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