- To: mathgroup at smc.vnet.net
- Subject: [mg26480] Re: question
- From: Alexandra Milik <amilik1 at compuserve.com>
- Date: Thu, 28 Dec 2000 02:52:20 -0500 (EST)
- References: <firstname.lastname@example.org> <email@example.com>
- Sender: owner-wri-mathgroup at wolfram.com
The equation has a first integral, it is
1/(u'+1) + Log[1+u'] + u^2/2= C
were C is the integration constant. So you can
try DSolve as well. Also you can check the NDSolve
solution using this formula.
"Kevin J. McCann" schrieb:
> The wise words of Abraham Boyarsky on 21 Dec 2000 02:36:29 -0500:
> > I believe the following is a Liouville differential equation:
> > u"[x] + u[x](u'[x] +1)^2 = 0
> > on [0,1].
> > How does one solve it?
> This is a nonlinear DE. I would use NDSolve with IC u==1,u'==0 and
> with u==0,u'==1.
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