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AW: ContourPlots,DensityPlots
*To*: mathgroup at smc.vnet.net
*Subject*: [mg23612] AW: [mg23558] ContourPlots,DensityPlots
*From*: Wolf Hartmut <hwolf at debis.com>
*Date*: Wed, 24 May 2000 02:16:12 -0400 (EDT)
*Sender*: owner-wri-mathgroup at wolfram.com
-----Ursprüngliche Nachricht-----
Von: Paul Hoke [SMTP:hokepaul at pilot.msu.edu]
Gesendet am: Samstag, 20. Mai 2000 09:11
An: mathgroup at smc.vnet.net
Betreff: [mg23558] ContourPlots,DensityPlots
Anybody have a lot of experience with ListContourPlot and
ListDensityPlot?
I have a matrix of data I want to plot and show for a presentation.
The problems I am having are as follows
with ColorFunctionScaling->True, It doesn't seem that the colors
have
any thing to do with the actual values if I use a legend and use
ColorFunction->Hue, the scale is on the plot doesn't equal the
legend
since the data is truncated to fit 0-1.
I'm trying to divide by the largest value since all my data is
positive
and then the legend color scheme should fit the data plot except I
don't
have a zero in my data to peg the lower end. I hate to add a zero
in my
matrix just to fix the lower end of the color scheme, is that the
only
option?
I can delineate which contours I want, but I can't label them. Is
there
anyway to print the value of contours? That is on the plot have
each
contour marked so that it isn't just a bunch of lines?
Dear Paul,
I needed some guessing . . . but perhaps this example might help you:
Let's define some data
data = Table[Sin[x y] Cos[x] + 2, {y, 0, Pi, 0.2}, {x, 0, 2Pi,
0.2}];
{Min[data], Max[data]}
{1.00674, 2.9862}
(roughly between 1 and 3)
We color the density plot in a certain way
p = ListDensityPlot[data, MeshRange -> {{0, 2 Pi}, {0, Pi}},
ColorFunction -> (Hue[#/3] &), ColorFunctionScaling -> False]
So 1 corresponds to Hue[1/3] (green) and 3 corresponds to Hue[1] (red), all
other values are in between (blue, violet, no yellow or orange). This is
reflected by the legend:
<< Graphics`Legend`
ShowLegend[ p,
{Hue[(2 # + 1)/3]&, 5, " 1", "3",
LegendPosition -> {1.1, -.4}}]
Why that (seemingly) different color function? within the legend the color
function is probed between 0 and 1 (in 5 steps here). So all we have to do
is to linearly map the interval {0, 1} to {min, max} of our applied color
function (when ColorFunctionScaling -> False).
So if you prefer to have the color scale at the legend reversed just do
ShowLegend[ p,
{Hue[(3 - 2 #)/3]&, 7, " 3", "1",
LegendPosition -> {1.1, -.4}}]
Kind regards, Hartmut
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