Re: Bugs in Abs and Sign !?
- To: mathgroup at smc.vnet.net
- Subject: [mg25752] Re: Bugs in Abs and Sign !?
- From: Brian Higgins <bghiggins at ucdavis.edu>
- Date: Sat, 21 Oct 2000 14:43:00 -0400 (EDT)
- References: <email@example.com> <firstname.lastname@example.org>
- Sender: owner-wri-mathgroup at wolfram.com
Bill Bertrum kindly pointed out to me that the replacement rule I suggested in my previous post does not work:I Abs[x^2] /. Abs -> fnt He is correct. The following rule does the trick In:=Abs[x^2] /. Power[Abs[x_], y_] -> fnt[Power[x, y]] Out=fnt[x^2] Brian n article <8smdh4$lcb at smc.vnet.net>, Brian Higgins <bghiggins at ucdavis.edu> wrote: > Jack, There is no bug in my opinion. Mathematica is doing pricesly > what you requested. When you use replacement rules it is wise to > carefully examine the FullForm of your expression. Thus > > FullForm[Abs[x^2] ] > > Power[Abs[x], 2] > > Hence > > Abs[x^2] /. Abs[u_] -> fnt[u] > > will give > > Power[ fnt[x] , 2] > > which is > > fnt[x]^2 > > The correct replacement rule for what you want to do is > > Abs[x^2] /. Abs -> fnt > > Cheers, > > Brian > > In article <8sjkr7$g3p at smc.vnet.net>, > Jack Goldberg <jackgold at umich.edu> wrote: > > Hi group. > > > > Try, > > > > Abs[x^2] /. Abs[u_] -> fnt[u] > > > > and > > > > Sign[x^2] /. Sign[u_] -> fnt[u] > > > > In each case I get fnt[x]^2. Shouldn't I get fnt[x^2]? After all, > > g[x^2] /. g[u_] -> fnt[u] returns fnt[x^2] which is what I have been > led > > to expect from Mathematica. I am using ver 4.01 on a PowerMac. > > > > These peculiarities are driving me crazy. This is the fourth "bug" > I have > > found in just 2 weeks. Please tell me I'm wrong. > > > > Thanks guys. > > > > Jack > > > > > > Sent via Deja.com http://www.deja.com/ > Before you buy. > > Sent via Deja.com http://www.deja.com/ Before you buy.