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Re: log x > x - proof?


Joe, it might take a while to do that; are you sure the
inequality points the way you intend it ?
jrc

Joe wrote:
> 
> Dear all,
> 
> Please could someone give me some hints as to how to prove that
> 
> log x > x for all x > 0
> 
> Isn't it proof by contradiction, or by intimidation?
> 
> Thanks in advance,
> 
> Joe


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