Re: Re: Random Sampling Without Replacement?

*To*: mathgroup at smc.vnet.net*Subject*: [mg26639] Re: [mg26608] Re: [mg26586] Random Sampling Without Replacement?*From*: "Richard Finley" <rfinley at medicine.umsmed.edu>*Date*: Sat, 13 Jan 2001 22:36:16 -0500 (EST)*Sender*: owner-wri-mathgroup at wolfram.com

Tomas, You are right about the package name...I just did it from memory and didn't check. But for the question, remember that it concerned drawing from a list of integers 1 to N which your example is not. For the problem as specified it works OK. RF. >>> Tomas Garza <tgarza01 at prodigy.net.mx> 01/11/01 01:20PM >>> I think there is an error in your suggestion (apart from the fact that the package is called DiscreteMath` - not DiscreteMathematics`). See, if the original list from which the samples are to be taken is e.g. {2, 4, 6, 8, 10, 12, 14, 16, 18, 20}, with size 10, then In[1]:= Take[RandomPermutation[10], 3] Out[1]= {1, 9, 10} and here you obtain two elements (1 and 9) who do not belong to the original list. Check, e.g., [mg26602] . Tomas Garza Mexico City -