Re: Equation

*To*: mathgroup at smc.vnet.net*Subject*: [mg26654] Re: Equation*From*: Lawrence Walker <lwalker701 at earthlink.net>*Date*: Sat, 13 Jan 2001 22:36:25 -0500 (EST)*Organization*: Morgan State University: COMSARE*References*: <93kn7o$747@smc.vnet.net>*Sender*: owner-wri-mathgroup at wolfram.com

I would use either of the following: where, equ = i == R - R((1 + .05)^10-1)/((1 + R)^10-1); 1. Solve[equ,R] 2. FindRoot[Evaluate[equ /. i -> 1], {R, .1}] Note that '1' gives a solution with Root in it implying that the solution can have multiple roots. '2' only finds a solution if you provide what is 'i' should be and where R should start. In this case 'i' was set to 1 and R is initially set to be 0.1 . Lawrence Jose Lasso wrote: > Hi, > > I have little experience with Mathematica, I change to Mathematica > few months ago, I want to solve: i = R - R((1 + .05)^10-1)/((1 + > R)^10-1) for R, how can I do this task in Mathematica??. Thx in > advance. Regards. > > Jose M Lasso > > PS:Happy new year!! -- ------------------------------------------------------------ (\___/) The fear of the LORD is the beginning of (o\ /o) wisdom: a good understanding have all they /|:.V.:|\ that do his commandments: his praise \\:::::// endureth for ever. Psa 111:10 -----`"" ""`------------------------------------------------ Lawrence A. Walker Jr., M.Eng./Ph.D. Candidate Morgan State University Clarence M. Mitchell School of Engineering COMSARE (Center Of Microwave/Satellite And RF Engineering) (443)885-1453 ------------------------------------------------------------