       Re: Equation

• To: mathgroup at smc.vnet.net
• Subject: [mg26654] Re: Equation
• From: Lawrence Walker <lwalker701 at earthlink.net>
• Date: Sat, 13 Jan 2001 22:36:25 -0500 (EST)
• Organization: Morgan State University: COMSARE
• References: <93kn7o\$747@smc.vnet.net>
• Sender: owner-wri-mathgroup at wolfram.com

```I would use either of the following:

where, equ = i == R - R((1 + .05)^10-1)/((1 + R)^10-1);

1.  Solve[equ,R]
2.  FindRoot[Evaluate[equ /. i -> 1], {R, .1}]

Note that '1' gives a solution with Root in it implying that the
solution can have multiple roots.  '2' only finds a solution if you
provide what is 'i' should be and where R should start.  In this case
'i' was set to 1 and R is initially set to be 0.1 .

Lawrence

Jose Lasso wrote:

> Hi,
>
> I have little experience with Mathematica, I change to Mathematica
> few months ago, I want to solve: i = R - R((1 + .05)^10-1)/((1 +
> R)^10-1) for R, how can I do this task in Mathematica??. Thx in
>
> Jose M Lasso
>
> PS:Happy new year!!

--

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Lawrence A. Walker Jr., M.Eng./Ph.D. Candidate
Morgan State University
Clarence M. Mitchell School of Engineering
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```

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