Transforming matrices
- To: mathgroup at smc.vnet.net
- Subject: [mg29665] Transforming matrices
- From: loopm at yahoo.com (Michael Loop)
- Date: Mon, 2 Jul 2001 02:20:26 -0400 (EDT)
- Organization: The Math Forum
- Sender: owner-wri-mathgroup at wolfram.com
I am a relatively new user of Mathematica, and I am having some trouble transforming a matrix. I would be appreciative of any advice. The problem is as follows. Given a randomly formed matrix of form: 0 0 1 2 2 2 0 0 0 0 0 0 1 2 0 1 2 2 2 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 2 2 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 Each digit represents a different state, and therefore each digits position must be preserved. I need to convert this matrix into a matrix of rates instead. The zeros will be converted into constant rates dependent on their position, and the rate will continue until a 1 is reached. Both 1 and 2 represent a rate of 0. So given a vector of rates: 40 38, 37, 36, 33, 32, 31, 30, 27, 23, 22, 21, 20, 16, 14, 13, 12, 10, 9, 6 I need to convert the first randomly generated matrix to look like: 40 40 0 0 0 0 32 32 32 32 32 32 0 0 16 0 0 0 0 9 40 40 40 40 40 40 40 40 40 40 40 40 40 40 40 40 40 40 40 40 40 40 0 0 0 0 32 32 32 32 32 32 32 32 32 32 32 32 32 32 Besides the fact that the rate must stay constant until a 1 is reached, the other subtlety of my problem is that when a rate starts over after a 1 or 2, the new rate must begin in the position of the next zero, but the rate must come from the position of the last 1 or 2. I can convert a matrix of this form on an individual basis using the Position and Table commands, but cannot find an efficient way of converting the matrix on a large scale. The matrix I actually need to convert is 240*1000, so if anyone can think of an efficient way of doing this I would be grateful for your input. Thank you. Micahel Loop Minneapolis, MN
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