RE: A tricky equation

• To: mathgroup at smc.vnet.net
• Subject: [mg29013] RE: [mg29005] A tricky equation
• From: "Higinio Ramos" <higra at gugu.usal.es>
• Date: Fri, 25 May 2001 01:47:52 -0400 (EDT)
• References: <200105240807.EAA04991@smc.vnet.net>
• Sender: owner-wri-mathgroup at wolfram.com

```----- Original Message -----
From: Anastasius Moumtzoglou <anas1 at hol.gr>
To: mathgroup at smc.vnet.net
Subject: [mg29013] [mg29005] A tricky equation

>
>
> I would be much obliged if you could help me with the following
> equation.
>
> b*k^(-a)-c*k^(-1)=1
>
> Mathematica returns that the above equation is a transcedental one. So,
> I'm thinking of linearization. Do you think there is a way to do it?
>
I suppose the unknown is k, and we don't know anything about a,b,c.
A way to solve for particular values of a,b,c :
In[33]:=
sol[a_, b_, c_] := Solve[b*k^(-a) - c*k^(-1) == 1, k]
In[34]:=
sol[2., 3, 4]
Out[34]=
{{k -> -4.64575}, {k -> 0.645751}}
In[35]:=
sol[.5, 3, 1]
Out[35]=
{{k -> 0.145898}, {k -> 6.8541}},etc.

```

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