RE: A tricky equation

*To*: mathgroup at smc.vnet.net*Subject*: [mg29013] RE: [mg29005] A tricky equation*From*: "Higinio Ramos" <higra at gugu.usal.es>*Date*: Fri, 25 May 2001 01:47:52 -0400 (EDT)*References*: <200105240807.EAA04991@smc.vnet.net>*Sender*: owner-wri-mathgroup at wolfram.com

----- Original Message ----- From: Anastasius Moumtzoglou <anas1 at hol.gr> To: mathgroup at smc.vnet.net Subject: [mg29013] [mg29005] A tricky equation > > > I would be much obliged if you could help me with the following > equation. > > b*k^(-a)-c*k^(-1)=1 > > Mathematica returns that the above equation is a transcedental one. So, > I'm thinking of linearization. Do you think there is a way to do it? > I suppose the unknown is k, and we don't know anything about a,b,c. A way to solve for particular values of a,b,c : In[33]:= sol[a_, b_, c_] := Solve[b*k^(-a) - c*k^(-1) == 1, k] In[34]:= sol[2., 3, 4] Out[34]= {{k -> -4.64575}, {k -> 0.645751}} In[35]:= sol[.5, 3, 1] Out[35]= {{k -> 0.145898}, {k -> 6.8541}},etc.

**References**:**A tricky equation***From:*"Anastasius Moumtzoglou" <anas1@hol.gr>