MathGroup Archive 2002

[Date Index] [Thread Index] [Author Index]

Search the Archive

RE: how to solve for periodic solution?

  • To: mathgroup at
  • Subject: [mg35736] RE: [mg35716] how to solve for periodic solution?
  • From: "DrBob" <majort at>
  • Date: Sun, 28 Jul 2002 03:32:10 -0400 (EDT)
  • Reply-to: <drbob at>
  • Sender: owner-wri-mathgroup at

Try algebra:

Solve[A[t] == S[t + P] - Log[2]/halflife*A[t], A[t]]

{{A[t] -> S[P + t]/ (1 + Log[2]/halflife)}}

That works no matter what values S takes on, so your one equation won't
let you solve for S between t1 and t2.

If A is known and you're solving for S, it's still algebra, but A would
have to satisfy the boundary conditions.

Bobby Treat

-----Original Message-----
From: tom [mailto:theiman at] 
To: mathgroup at
Subject: [mg35736] [mg35716] how to solve for periodic solution?


I have no clue as to how to proceed to solve the equation below.
Any ideas on how to solve for the periodic solution of this equation
would be most appreciated!! Thankyou!!


S(t+P) = S(t)  if t1<t<t2
S(t+P) = 0 otherwise

where P is the period of the system
t is the time at which a sample is taken
t1 is the beginning of a discontinuity
t2 is the end of a discontinuity
A(t) is the abundance at time t

I want to fit data to the resulting equation and find t1 and t2



  • Prev by Date: Re: Front End on Mac OS X
  • Next by Date: Package Puzzlers?
  • Previous by thread: how to solve for periodic solution?
  • Next by thread: Re: how to solve for periodic solution?