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Re: calculating the azimuth between two lat/lon's


Hmm, the "new" argument must by Ver. 4 specific. I'm still using Ver. 3 :<(

"Peter" <peter1963 at totalise.co.uk> wrote in message
news:aepl49$s1i$1 at smc.vnet.net...

> See the help browser:
>
> Mod[m, n, d] gives a result x such that d <= x <= d+n and x mod n == m mod
n
>
> So in this case the result lies in [-Pi,Pi]
>
> Peter
>
>




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