Constant function Integrate Assumption - More
- To: mathgroup at smc.vnet.net
- Subject: [mg47252] Constant function Integrate Assumption - More
- From: "Reece, Daryl" <Daryl.Reece at goody.com>
- Date: Thu, 1 Apr 2004 00:03:41 -0500 (EST)
- Sender: owner-wri-mathgroup at wolfram.com
Many thanks to everyone offering solutions to my dilemma. In trying to simplify the problem, I must have slipped up and oversimplified. Specifically I want to start with Integrate[50000 Units/Year UnitStep[(t-5 Month)/Month], t] and receive 50000 Units/Year (t-5 Month) UnitStep[(t-5 Month)/Month]. I need the full answer so that the units work out correctly in the answer. I am starting with a sale rate and want to derive the total sales as a function of time. This time may then be input as Days, Months, Years.... If I perform the replace operation, as many of you suggest, this ability disappears. A lister rightly pointed out that Mathematica is confused not because it assumes that Month may be a function of t, but rather it does not know the sign of Month. Even using the assumption Month>0 does not fix the problem. Other suggestions?
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