       Re: How to evaluate Exp[I Pi(1+x)]? version=2.55

• To: mathgroup at smc.vnet.net
• Subject: [mg52766] Re: [mg52702] How to evaluate Exp[I Pi(1+x)]? version=2.55
• From: Andrzej Kozlowski <akoz at mimuw.edu.pl>
• Date: Mon, 13 Dec 2004 04:22:00 -0500 (EST)
• References: <200412100123.UAA18952@smc.vnet.net> <5EBEEE06-4A51-11D9-BF9A-000A95B4967A@mimuw.edu.pl>
• Sender: owner-wri-mathgroup at wolfram.com

```I assumed that x is real, which is of course unnecessary. One can use:

FullSimplify[ComplexExpand[Exp[I*Pi*(1 + x)], {x}]]

-E^(I*Pi*x)

which does not make this assumption.

Andrzej

On 10 Dec 2004, at 11:15, Andrzej Kozlowski wrote:

>
> On 10 Dec 2004, at 10:23, hello wrote:
>
>> Is there a way to evaluate Exp[I Pi (1+x)]? I am expecting to see the
>> result to be:
>>
>> -Exp[I Pi x]
>>
>> because Exp[I Pi] can be reduced to shorter form.
>>
>>
>>
>>
>
> Hello?
>
> FullSimplify[ComplexExpand[Exp[I*Pi*(1 + x)]],
>   x \$B":(B Reals]
>
>
> -E^(I*Pi*x)
>
>
>
> Andrzej Kozlowski
> Chiba, Japan
> http://www.akikoz.net/~andrzej/
> http://www.mimuw.edu.pl/~akoz/
>

```

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