Re: How to evaluate Exp[I Pi(1+x)]? version=2.55

*To*: mathgroup at smc.vnet.net*Subject*: [mg52766] Re: [mg52702] How to evaluate Exp[I Pi(1+x)]? version=2.55*From*: Andrzej Kozlowski <akoz at mimuw.edu.pl>*Date*: Mon, 13 Dec 2004 04:22:00 -0500 (EST)*References*: <200412100123.UAA18952@smc.vnet.net> <5EBEEE06-4A51-11D9-BF9A-000A95B4967A@mimuw.edu.pl>*Sender*: owner-wri-mathgroup at wolfram.com

I assumed that x is real, which is of course unnecessary. One can use: FullSimplify[ComplexExpand[Exp[I*Pi*(1 + x)], {x}]] -E^(I*Pi*x) which does not make this assumption. Andrzej On 10 Dec 2004, at 11:15, Andrzej Kozlowski wrote: > > On 10 Dec 2004, at 10:23, hello wrote: > >> Is there a way to evaluate Exp[I Pi (1+x)]? I am expecting to see the >> result to be: >> >> -Exp[I Pi x] >> >> because Exp[I Pi] can be reduced to shorter form. >> >> >> >> > > Hello? > > FullSimplify[ComplexExpand[Exp[I*Pi*(1 + x)]], > x $B":(B Reals] > > > -E^(I*Pi*x) > > > > Andrzej Kozlowski > Chiba, Japan > http://www.akikoz.net/~andrzej/ > http://www.mimuw.edu.pl/~akoz/ >

**References**:**How to evaluate Exp[I Pi(1+x)]?***From:*hello@noreply.com (hello)