[Date Index]
[Thread Index]
[Author Index]
Re: How to evaluate Exp[I Pi(1+x)]?
*To*: mathgroup at smc.vnet.net
*Subject*: [mg52770] Re: How to evaluate Exp[I Pi(1+x)]?
*From*: "Dr. Wolfgang Hintze" <weh at snafu.de>
*Date*: Mon, 13 Dec 2004 04:22:09 -0500 (EST)
*References*: <200412100123.UAA18952@smc.vnet.net> <cpehuc$6hr$1@smc.vnet.net>
*Sender*: owner-wri-mathgroup at wolfram.com
I remember that ComplexExpand[expr] assumes parameters in expr to be
real. Hence the following was the shortest succesful expansion I found:
In[4]:=
FullSimplify[ComplexExpand[E^(I*Pi*(1 + x))]]
Out[4]=
-E^(I*Pi*x)
Simplify is not enough.
By the way, while doing much complex function work recently I devolped
the habit to always use ComplexExpand as the first opration.
Otherwise even the simplest operations Re, Im, Abs don't work.
Regards,
Wolfgang
Andrzej Kozlowski wrote:
> On 10 Dec 2004, at 10:23, hello wrote:
>
>
>>Is there a way to evaluate Exp[I Pi (1+x)]? I am expecting to see the
>>result to be:
>>
>>-Exp[I Pi x]
>>
>>because Exp[I Pi] can be reduced to shorter form.
>>
>>
>>
>>
>>
>
> Hello?
>
> FullSimplify[ComplexExpand[Exp[I*Pi*(1 + x)]],
> x $B":(B Reals]
>
>
> -E^(I*Pi*x)
>
>
>
> Andrzej Kozlowski
> Chiba, Japan
> http://www.akikoz.net/~andrzej/
> http://www.mimuw.edu.pl/~akoz/
>
>
Prev by Date:
**Re: Suse 9.2 + mathematica 5.0 problem**
Next by Date:
**How to express ODE?**
Previous by thread:
**Re: How to evaluate Exp[I Pi(1+x)]? version=2.55**
Next by thread:
**Re: Re: How to evaluate Exp[I Pi(1+x)]?**
| |