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MathGroup Archive 2004

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Re: 3D Pascal's beta cube

  • To: mathgroup at smc.vnet.net
  • Subject: [mg49634] Re: [mg49610] 3D Pascal's beta cube
  • From: DrBob <drbob at bigfoot.com>
  • Date: Sun, 25 Jul 2004 02:55:39 -0400 (EDT)
  • References: <200407211814.i6LIELN23030@proapp.mathforum.org> <cdnq13$l3v$1@smc.vnet.net> <200407240748.DAA05907@smc.vnet.net>
  • Reply-to: drbob at bigfoot.com
  • Sender: owner-wri-mathgroup at wolfram.com

Very nice!

Bobby

On Sat, 24 Jul 2004 03:48:19 -0400 (EDT), Roger L. Bagula <rlbtftn at netscape.net> wrote:

> (* 64*64*64 CUBE OF xy,yz,zx  beta triangle 3D *)
> (* BY R. L. BAGULA 23 July 2004©*)
>
> a=32;
>
> b1=Beta[Abs[a-Abs[a-x]],Abs[a-Abs[a-y]]]
> b2=Beta[Abs[a-Abs[a-y]],Abs[a-Abs[a-z]]]
> b3=Beta[Abs[a-Abs[a-x]],Abs[a-Abs[a-z]]]
>
> g=Flatten[Table[If[Mod[1/(b1*b2*b3),2]==1,
> Cuboid[0.5*{x,y,z}],{}],
> {x,0,2*a},{y,0,2*a},{z,0,2*a}]];
>
> gg=Show[Graphics3D[g,Boxed->False,ViewPoint->{-3.059, 8.168, 2.221}]]
>
> Notebook available by request.
> Roger L. Bagula wrote:
>> There is and old Visualization in Mathematica that
>> gives a modulo 2 version of a Pascal's triangle.
>> It is a right angle version of a tetrahedral 3d Sierpiski triangle.
>> Here it is: ( copyright Mathematica):
>>
>> g=Flatten[Table[If
>> Mod[Multinomial[x,y,x],2]==1,Cuboid[1.2*{x,y,-z}}],{}],{x,0,15},{y.0,15},{z,0,15}]
>> Show[Graphics3D[g]]
>>
>> phil wrote:
>>
>>> Is there a three dimensional version of Pascal's
>>> triangle? If so, I suppose it would be a cone (?).
>>> Applications?
>>>
>>> phil
>>>
>>
>>
>>
>
>



-- 
DrBob at bigfoot.com
www.eclecticdreams.net


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