Mathematica 9 is now available
Services & Resources / Wolfram Forums
-----
 /
MathGroup Archive
2004
*January
*February
*March
*April
*May
*June
*July
*August
*September
*October
*November
*December
*Archive Index
*Ask about this page
*Print this page
*Give us feedback
*Sign up for the Wolfram Insider

MathGroup Archive 2004

[Date Index] [Thread Index] [Author Index]

Search the Archive

Re: Basic conditional statement question.

  • To: mathgroup at smc.vnet.net
  • Subject: [mg48688] Re: [mg48653] Basic conditional statement question.
  • From: DrBob <drbob at bigfoot.com>
  • Date: Thu, 10 Jun 2004 02:44:12 -0400 (EDT)
  • References: <200406090817.EAA15671@smc.vnet.net>
  • Sender: owner-wri-mathgroup at wolfram.com

Either of these will work for you, I think:

If[a == 0, Null, Print["such and such"], Print["such and such"]]
"such and such"

If[ !TrueQ[a == 0], Print["such and such"]]
"such and such"

Bobby

On Wed, 9 Jun 2004 04:17:30 -0400 (EDT), Scott <jujio77 at yahoo.com> wrote:

> Here is a question I would think has a simple solution.  Let's say I
> have some variable "a" which is an integer, but I haven't defined it
> in Mathematica.  I want to run a conditional statement on it.
> Basically
>
> If[a!=0,Print["such and such"]]
>
> When I do something like this, Mathematica I asume is spitting out a
> null statement, because it doesn't do anything.  So, how can I define
> "a" such that Mathematica knows it isn't =0 yet, still some integer.
>
> The reason I ask is I am calculating Christophel symbols (and such)
> and many of them =0, so I want to only output those that are not equal
> to zero.
>
> Thanks for any help,
> Scott
>
>



-- 
DrBob at bigfoot.com
www.eclecticdreams.net/index.html


  • Prev by Date: Re: FullSimplify Question
  • Next by Date: Re: seruous solve bug? only when used with simplifying
  • Previous by thread: Basic conditional statement question.
  • Next by thread: Re: Basic conditional statement question.