RE: proof of formula for log(-t) found in Mathematica?
- To: mathgroup at smc.vnet.net
- Subject: [mg48281] RE: [mg48194] proof of formula for log(-t) found in Mathematica?
- From: "Dr A.H. Harker" <a.harker at ucl.ac.uk>
- Date: Fri, 21 May 2004 03:54:29 -0400 (EDT)
- Sender: owner-wri-mathgroup at wolfram.com
Is it really built into Mathematica? Certainly V5.0, given Log[-t] == Log[t^2]/2 + I*Arg[-t] does not return True. Which is just as well, as t^2 and the square modulus of t are not the same (unless t happens to be real). Dr A.H. Harker Director of Postgraduate Studies Deputy Head, Condensed Matter and Materials Physics Group Department of Physics and Astronomy University College London Gower Street LONDON WC1E 6BT (44)(0)207 679 3404 a.harker at ucl.ac.uk -----Original Message----- From: Roger L. Bagula [mailto:rlbtftn at netscape.net] To: mathgroup at smc.vnet.net Subject: [mg48281] [mg48194] proof of formula for log(-t) found in Mathematica? I found this while doing work on complex exponents: f(t)=Log[-t]=Log[t^2]/2+I*Arg[-t] It is a result built into Mathematica. I would like to see how it is derived as it seem counter intuitive in it's results. Respectfully, Roger L. Bagula