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Re: proof of formula for log(-t) found in Mathematica?


ComplexExpand[Log[-t]]=Log[t^2]/2+I*Arg[-t]
No absolute value is given.
Roger L. Bagula wrote:
> I found this while doing work on complex exponents:
> 
> f(t)=Log[-t]=Log[t^2]/2+I*Arg[-t]
> 
> It is a result built into Mathematica.
> I would like to see how it is derived as it seem counter intuitive in 
> it's results.
> Respectfully,
> Roger L. Bagula
> 


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