Re: Problem with function
- To: mathgroup at smc.vnet.net
- Subject: [mg48316] Re: Problem with function
- From: "Steve Luttrell" <steve_usenet at _removemefirst_luttrell.org.uk>
- Date: Mon, 24 May 2004 00:45:10 -0400 (EDT)
- References: <c8ptmu$kne$1@smc.vnet.net>
- Sender: owner-wri-mathgroup at wolfram.com
Define your function. f[t_] := (UnitStep[t] - UnitStep[t - 1])*t + (UnitStep[t - 1] - UnitStep[t - 3])*(3/2 - t/2) Fourier transform your function. Expand[FourierTransform[f[t], t, \[Omega]]] which gives -(1/(Sqrt[2*Pi]*\[Omega]^2)) + (3*E^(I*\[Omega]))/ (2*Sqrt[2*Pi]*\[Omega]^2) - E^(3*I*\[Omega])/ (2*Sqrt[2*Pi]*\[Omega]^2) - I*Sqrt[Pi/2]* Derivative[1][DiracDelta][\[Omega]] + (3/2)*I*E^(I*\[Omega])*Sqrt[Pi/2]* Derivative[1][DiracDelta][\[Omega]] - (1/2)*I*E^(3*I*\[Omega])*Sqrt[Pi/2]* Derivative[1][DiracDelta][\[Omega]] Steve Luttrell "DJkapi" <djkapi at poczta.onet.pl> wrote in message news:c8ptmu$kne$1 at smc.vnet.net... > How to compute in Mathematica fourier transform of function: > > t ,0=< t =<1 > g(t)= > 1.5-0.5t , 1< t =<3 > > to tell the truth i dont even know how to make Mathematica print that > function. > > Regards, > DJKapi > >