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MathGroup Archive 2004

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Re: finding explicit rule for series

  • To: mathgroup at smc.vnet.net
  • Subject: [mg52054] Re: [mg52043] finding explicit rule for series
  • From: DrBob <drbob at bigfoot.com>
  • Date: Tue, 9 Nov 2004 01:36:38 -0500 (EST)
  • References: <200411080813.DAA07931@smc.vnet.net>
  • Reply-to: drbob at bigfoot.com
  • Sender: owner-wri-mathgroup at wolfram.com

It turns out that n[i] == 5342543 i + n[0].

n[i_?Positive]:=5342543+n[i-1]
n/@Range@5
5342543Range@5+n[0]

{5342543+n[0],10685086+n[0],16027629+n[0],21370172+n[0],26712715+n[0]}

{5342543+n[0],10685086+n[0],16027629+n[0],21370172+n[0],26712715+n[0]}

I calculated a few terms both ways and the answers agree.

Bobby

On Mon, 8 Nov 2004 03:13:28 -0500 (EST), Uwe Ziegenhagen <newsgroup at ziegenhagen.info> wrote:

> Hello,
>
> i have a series of numbers and would like to use Mathematica to find the
> explicit algorithm in that way:
>
> n(i)=5342543+n(i-1)....
>
> I already spent some time with the manual, but didn't find anything.
>
> Uwe
>



-- 
DrBob at bigfoot.com
www.eclecticdreams.net


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