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Re: UnitStep


You want to take a limit rather than do a replacement (which is what you use 
of /.p->0 does).

Limit[(1/p) UnitStep[p-1] , p->0]

Steve Luttrell

"Blimbaum, Jerry AA R22" <jerry.blimbaum at navy.mil> wrote in message 
news:cnuoh9$sql$1 at smc.vnet.net...
> Why does the following give me 'indeterminate, infinite expression
> encountered', etc. instead of  zero....
>
>
> (1/p) UnitStep[p-1] /.p->0
>
>
> I defined a function using the UnitStep because p could  = 0  and I
> thought this would be the way around that problem.......but didnt work
> the way I expected.....
>
>
> jerry blimbaum
>
> 



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